[address-policy-wg] RE: an arithmetic lesson
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michael.dillon at bt.com
michael.dillon at bt.com
Thu Dec 3 13:23:49 CET 2009
> On 3 Dec 2009, at 10:00, <michael.dillon at bt.com> wrote: > > > an IPv6 /24 and an IPv4 /24 use up the same percentage of the total > > address space. > > How do you work that out? Please enlighten me. 2^24/2^128 x > 100 is many orders of magnitude smaller than 2^24/2^32 x 100: > gromit% bc > scale=50 > 2^24/2^128*100 > .00000000000000000000000000000493038065763132378300 > 2^24/2^32*100 > .39062500000000000000000000000000000000000000000000 > > There are of course the same number of IPv4 and IPv6 /24s. Percentage is calculated by dividing the number of things under consideration by the total number of things. When I used the word "an", I meant one thing. Assuming that the number of IPv4 and IPv6 /24s is 10 1/10 = 1/10 Assuming that the number of IPv4 and IPv6 /24s is 8192 1/8192 = 1/8192 Assuming that the number of IPv4 and IPv6 /24s is 2882873787 1/2882873787 = 1/2882873787 Do you see a pattern forming? --Michael Dillon
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