Re: SV: how 200 /48's fails the job [Re: [address-policy-wg] Policy proposal: #gamma IPv6 Initial Allocation Criteria]
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To: Jørgen Hovland <>
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From: Gert Doering <>
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Date: Thu, 7 Apr 2005 21:00:33 +0200
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Cc: "'Iljitsch van Beijnum'" <>,
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Comment: DomainKeys? See http://antispam.yahoo.com/domainkeys
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Hi,
On Thu, Apr 07, 2005 at 12:21:06AM +0200, Jørgen Hovland wrote:
> How long do you think this /48 policy will last? I was hoping for
> at least 60 years++ so I don't need to have the same discussion
> again with IPv8.
While I personally dislike /64s and /48s (for some other reasons that
do not need discussion here, as there are good reasons for /64 and /48,
and I can accept these), your argumentation is still flawed.
Everybody that tells me "we will run out of IPv6 address space!!!!" has
pretty obviously not done the math - just count how many /48s are there,
and then do some estimation on how many people earth can suffice, and
how many /48s per person for each of those we have. Out of 2000::/3.
*Then* come back and tell me (with a straight face) "we will run out
of IPv6 addresses because /48s are such a great waste".
[..]
> So you are saying that documenting your need of a /48 will be
> rejected by future LIRs due to their own address policy and they
> will give you a /56 instead because that???s what their policy says?
The whole point of the /48s is that you do NOT need to argue with your
LIR. You'll *always* get a /48 when changing ISPs, and that's big enough
for all but the largest customers. This is why /48s are *good*.
(Unless, of course, your network is too large for a /48 - provisions
for that case exist).
> I don't believe that will happen as long as the RIRs have somewhat
> loose policies. ARIN allocates you a netblock and you do whatever
> you want with it. With RIPE you need to apply for allocations within
> your assigned netblock.
You're seriously confused about terminology and about RIPE IPv6 policy.
[..]
> But what about you document the need of a /40 but will only get a /48 (/47)?
Show me the network plan that documents the need for a /40. 16 million
independent multiaccess networks ("LAN")??? (There are some, but it's
going to be "few").
Gert Doering
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